-16x^2+55x+10=0

Solution for -16x^2+55x+10=0 equation:

-16x^2+55x+10=0

a = -16; b = 55; c = +10;
Δ = b2-4ac
Δ = 552-4·(-16)·10
Δ = 3665
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-\sqrt{3665}}{2*-16}=\frac{-55-\sqrt{3665}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+\sqrt{3665}}{2*-16}=\frac{-55+\sqrt{3665}}{-32}
$